Molar Mass of (NH4)2Cr2O7 (Ammonium Dichromate)

Molar Mass Calculator

What is the molar mass of (NH₄)₂Cr₂O₇?

Answer

M((NH₄)₂Cr₂O₇) =

252.063 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024).

(NH₄)₂Cr₂O₇ = 2 × (N + 4 H) + 2 Cr + 7 O → N 2, H 8, Cr 2, O 7

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Nnitrogen	2	14.007	28.014 w ≈ 11.11%	≈ 11.11%
Hhydrogen	8	1.0080	8.0640 w ≈ 3.20%	≈ 3.20%
Crchromium	2	51.996	103.992 w ≈ 41.26%	≈ 41.26%
Ooxygen	7	15.999	111.993 w ≈ 44.43%	≈ 44.43%
Σ = 252.063 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

O 44.43%Cr 41.26%

N 11.11%H 3.20%

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Molar masses of substances nearby

Formula	M, g/mol
MgSO₄·7H₂O (magnesium sulfate heptahydrate)	246.47
Ag₂S (silver sulfide)	247.80
CuSO₄·5H₂O (copper(II) sulfate pentahydrate)	249.68
(NH₄)₂Cr₂O₇ (ammonium dichromate)	252.063
BaCrO₄ (barium chromate)	253.32
I₂ (iodine)	253.80
S₈ (octasulfur)	256.48

FAQ

What is the molar mass of (NH4)2Cr2O7?

M((NH₄)₂Cr₂O₇) = 252.063 g/mol

How to calculate the molar mass of (NH₄)₂Cr₂O₇?

Add up the atomic weights of all the atoms in the formula: 2 × 14.007 + 8 × 1.0080 + 2 × 51.996 + 7 × 15.999 = 252.063 g/mol.

How many grams are in 2 moles of (NH₄)₂Cr₂O₇?

m = n × M = 2 mol × 252.063 g/mol = 504.126 g.

See Also