Molar Mass of (NH4)2CO3 (Ammonium Carbonate)
Molar Mass Calculator
What is the molar mass of (NH4)2CO3?
Answer
M((NH4)2CO3) =
96.086 g/mol
Atomic weights: IUPAC standard values (CIAAW, 2024).
(NH4)2CO3 = 2 × (N + 4 H) + C + 3 O → N 2, H 8, C 1, O 3
| Element | Atoms, n | Atomic weight, A | n × A, g/mol Mass fraction, w | |
|---|---|---|---|---|
| Nnitrogen | 2 | 14.007 | 28.014 w ≈ 29.16% | ≈ 29.16% |
| Hhydrogen | 8 | 1.0080 | 8.0640 w ≈ 8.39% | ≈ 8.39% |
| Ccarbon | 1 | 12.011 | 12.011 w ≈ 12.50% | ≈ 12.50% |
| Ooxygen | 3 | 15.999 | 47.997 w ≈ 49.95% | ≈ 49.95% |
| Σ = 96.086 g/mol w = 100% | 100% | |||
Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)
O 49.95%
N 29.16%C 12.50%H 8.39%
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Molar masses of substances nearby
| Formula | M, g/mol |
|---|---|
| CuS (copper monosulfide) | 95.61 |
| Mo (molybdenum) | 95.95 |
| NaC₃H₅O₂ (sodium propionate) | 96.061 |
| (NH₄)₂CO₃ (ammonium carbonate) | 96.086 |
| CoF₂ (cobalt(II) fluoride) | 96.929 |
| KSCN (potassium thiocyanate) | 97.18 |
| ZnS (zinc sulfide) | 97.44 |
FAQ
What is the molar mass of (NH4)2CO3?
M((NH₄)₂CO₃) = 96.086 g/mol
How to calculate the molar mass of (NH₄)₂CO₃?
Add up the atomic weights of all the atoms in the formula: 2 × 14.007 + 8 × 1.0080 + 12.011 + 3 × 15.999 = 96.086 g/mol.
How many grams are in 2 moles of (NH₄)₂CO₃?
m = n × M = 2 mol × 96.086 g/mol = 192.172 g.
See Also
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- Молярная масса (NH4)2CO3 (карбонат аммония): расчёт
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