Molar Mass of (CH3COO)2Zn (Zinc Acetate)

Molar Mass Calculator

What is the molar mass of (CH₃COO)₂Zn?

Answer

M((CH₃COO)₂Zn) ≈

183.47 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — Zn: 65.38.

(CH₃COO)₂Zn = 2 × (C + 3 H + C + O + O) + Zn → C 4, H 6, O 4, Zn 1

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Ccarbon	4	12.011	48.044 w ≈ 26.19%	≈ 26.19%
Hhydrogen	6	1.0080	6.0480 w ≈ 3.30%	≈ 3.30%
Ooxygen	4	15.999	63.996 w ≈ 34.88%	≈ 34.88%
Znzinc	1	65.38	65.38 w ≈ 35.64%	≈ 35.64%
Σ = 183.468 ≈ 183.47 g/mol w = 100%				100%

Each fraction is rounded on its own, so the printed ones add up to 100.01%; unrounded, they make exactly 100%.

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

Zn 35.64%

O 34.88%C 26.19%H 3.30%

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Molar masses of substances nearby

Formula	M, g/mol
Co(NO₃)₂ (cobalt(II) nitrate)	182.941
C₇H₅NO₃S (saccharin)	183.18
C₉H₁₃NO₃ (epinephrine)	183.207
(CH₃COO)₂Zn (zinc acetate)	183.47
CuFeS₂	183.51
SrSO₄ (strontium sulfate)	183.68
W (tungsten)	183.84

FAQ

What is the molar mass of (CH3COO)2Zn?

M((CH₃COO)₂Zn) ≈ 183.47 g/mol

How to calculate the molar mass of (CH₃COO)₂Zn?

Add up the atomic weights of all the atoms in the formula: 4 × 12.011 + 6 × 1.0080 + 4 × 15.999 + 65.38 = 183.468 ≈ 183.47 g/mol.

How many grams are in 2 moles of (CH₃COO)₂Zn?

m = n × M = 2 mol × 183.47 g/mol = 366.94 g.

See Also