Molar Mass of (CH3COO)2Cu (Copper(II) Acetate)
Molar Mass Calculator
What is the molar mass of (CH3COO)2Cu?
Answer
M((CH3COO)2Cu) =
181.634 g/mol
Atomic weights: IUPAC standard values (CIAAW, 2024).
(CH3COO)2Cu = 2 × (C + 3 H + C + O + O) + Cu → C 4, H 6, O 4, Cu 1
| Element | Atoms, n | Atomic weight, A | n × A, g/mol Mass fraction, w | |
|---|---|---|---|---|
| Ccarbon | 4 | 12.011 | 48.044 w ≈ 26.45% | ≈ 26.45% |
| Hhydrogen | 6 | 1.0080 | 6.0480 w ≈ 3.33% | ≈ 3.33% |
| Ooxygen | 4 | 15.999 | 63.996 w ≈ 35.23% | ≈ 35.23% |
| Cucopper | 1 | 63.546 | 63.546 w ≈ 34.99% | ≈ 34.99% |
| Σ = 181.634 g/mol w = 100% | 100% | |||
Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)
O 35.23%
Cu 34.99%C 26.45%H 3.33%
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Molar masses of substances nearby
| Formula | M, g/mol |
|---|---|
| C₆H₁₂O₆ (glucose) | 180.156 |
| C₉H₈O₄ (aspirin) | 180.159 |
| Ta (tantalum) | 180.95 |
| (CH₃COO)₂Cu (copper(II) acetate) | 181.634 |
| V₂O₅ (vanadium(V) oxide) | 181.879 |
| C₆H₁₄O₆ (D-sorbitol) | 182.172 |
| C₁₃H₁₀O (benzophenone) | 182.222 |
FAQ
What is the molar mass of (CH3COO)2Cu?
M((CH₃COO)₂Cu) = 181.634 g/mol
How to calculate the molar mass of (CH₃COO)₂Cu?
Add up the atomic weights of all the atoms in the formula: 4 × 12.011 + 6 × 1.0080 + 4 × 15.999 + 63.546 = 181.634 g/mol.
How many grams are in 2 moles of (CH₃COO)₂Cu?
m = n × M = 2 mol × 181.634 g/mol = 363.268 g.
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