Molar Mass of PbS (Lead(II) Sulfide)

Molar Mass Calculator

What is the molar mass of PbS?

Answer

M(PbS) ≈

239.3 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — Pb: 207.2.

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Pblead	1	207.2	207.2 w ≈ 86.60%	≈ 86.60%
Ssulfur	1	32.06	32.06 w ≈ 13.40%	≈ 13.40%
Σ = 239.26 ≈ 239.3 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

Pb 86.60%

S 13.40%

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Molar masses of substances nearby

Formula	M, g/mol
CdN₂O₆ (cadmium nitrate)	236.42
U (uranium)	238.03
PbO₂ (lead dioxide)	239.2
PbS (lead(II) sulfide)	239.3
Pb(OH)₂ (lead(II) hydroxide)	241.2
Fe(NO₃)₃ (ferric nitrate)	241.857
BaCl₂·2H₂O (barium chloride dihydrate)	244.26

FAQ

What is the molar mass of PbS?

M(PbS) ≈ 239.3 g/mol

How to calculate the molar mass of PbS?

Add up the atomic weights of all the atoms in the formula: 207.2 + 32.06 = 239.26 ≈ 239.3 g/mol.

How many grams are in 2 moles of PbS?

m = n × M = 2 mol × 239.3 g/mol = 478.6 g.

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