Molar Mass of Na2HPO4 (Dibasic Sodium Phosphate)

Molar Mass Calculator

What is the molar mass of Na₂HPO₄?

Answer

M(Na₂HPO₄) =

141.958 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024).

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Nasodium	2	22.990	45.980 w ≈ 32.39%	≈ 32.39%
Hhydrogen	1	1.0080	1.0080 w ≈ 0.71%	≈ 0.71%
Pphosphorus	1	30.974	30.974 w ≈ 21.82%	≈ 21.82%
Ooxygen	4	15.999	63.996 w ≈ 45.08%	≈ 45.08%
Σ = 141.958 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

O 45.08%

Na 32.39%P 21.82%H 0.71%

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Molar masses of substances nearby

Formula	M, g/mol
NaMnO₄ (sodium permanganate)	141.924
AsH₃O₄ (arsenic acid)	141.942
P₂O₅ (phosphorus pentoxide)	141.943
Na₂HPO₄ (dibasic sodium phosphate)	141.958
Na₂SO₄ (sodium sulfate)	142.04
C₁₀H₂₂ (decane)	142.286
Ca(ClO)₂ (calcium hypochlorite)	142.98

FAQ

What is the molar mass of Na2HPO4?

M(Na₂HPO₄) = 141.958 g/mol

How to calculate the molar mass of Na₂HPO₄?

Add up the atomic weights of all the atoms in the formula: 2 × 22.990 + 1.0080 + 30.974 + 4 × 15.999 = 141.958 g/mol.

How many grams are in 2 moles of Na₂HPO₄?

m = n × M = 2 mol × 141.958 g/mol = 283.916 g.

See Also