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    Molar Mass of NaMnO4 (Sodium Permanganate)

    Molar Mass Calculator
    Chemical formula

    What is the molar mass of NaMnO4?

    Answer

    M(NaMnO4) =
    141.924 g/mol

    Atomic weights: IUPAC standard values (CIAAW, 2024).

    Contribution of each element
    Element Atoms, n Atomic weight, A n × A, g/mol Mass fraction, w
    Nasodium122.99022.990 w ≈ 16.20%
    Mnmanganese154.93854.938 w ≈ 38.71%
    Ooxygen415.99963.996 w ≈ 45.09%
    Σ = 141.924 g/mol w = 100%

    Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

    Mass fractions of the elements

    Na 16.20%

    See Also

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    Molar Mass of NaMnO4 (Sodium Permanganate): Step by Step. M(NaMnO4) = 141.924 g/mol: 22.990 (Na) + 54.938 (Mn) + 4 × 15.999 (O). Mass fractions: O 45.09%, Mn 38.71%, Na 16.20%.
    https://calculat.io/en/other/molar-mass/namno4/generated.jpgCopy

    FAQ

    What is the molar mass of NaMnO4?

    M(NaMnO₄) = 141.924 g/mol

    How to calculate the molar mass of NaMnO₄?

    Add up the atomic weights of all the atoms in the formula: 22.990 + 54.938 + 4 × 15.999 = 141.924 g/mol.

    How many grams are in 2 moles of NaMnO₄?

    m = n × M = 2 mol × 141.924 g/mol = 283.848 g.