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    Molar Mass of Na2HPO4 (Dibasic Sodium Phosphate)

    Molar Mass Calculator
    Chemical formula

    What is the molar mass of Na2HPO4?

    Answer

    M(Na2HPO4) =
    141.958 g/mol

    Atomic weights: IUPAC standard values (CIAAW, 2024).

    Contribution of each element
    Element Atoms, n Atomic weight, A n × A, g/mol Mass fraction, w
    Nasodium222.99045.980 w ≈ 32.39%
    Hhydrogen11.00801.0080 w ≈ 0.71%
    Pphosphorus130.97430.974 w ≈ 21.82%
    Ooxygen415.99963.996 w ≈ 45.08%
    Σ = 141.958 g/mol w = 100%

    Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

    Mass fractions of the elements

    Na 32.39%P 21.82%H 0.71%

    See Also

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    Molar Mass of Na2HPO4 (Dibasic Sodium Phosphate). M(Na2HPO4) = 141.958 g/mol: 2 × 22.990 (Na) + 1.0080 (H) + 30.974 (P) + 4 × 15.999 (O). Mass fractions: O 45.08%, Na 32.39%, P 21.82%.
    https://calculat.io/en/other/molar-mass/na2hpo4/generated.jpgCopy

    FAQ

    What is the molar mass of Na2HPO4?

    M(Na₂HPO₄) = 141.958 g/mol

    How to calculate the molar mass of Na₂HPO₄?

    Add up the atomic weights of all the atoms in the formula: 2 × 22.990 + 1.0080 + 30.974 + 4 × 15.999 = 141.958 g/mol.

    How many grams are in 2 moles of Na₂HPO₄?

    m = n × M = 2 mol × 141.958 g/mol = 283.916 g.