Molar Mass of Na2B4O7

Molar Mass Calculator

What is the molar mass of Na₂B₄O₇?

Answer

M(Na₂B₄O₇) ≈

201.21 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — B: 10.81.

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Nasodium	2	22.990	45.980 w ≈ 22.85%	≈ 22.85%
Bboron	4	10.81	43.24 w ≈ 21.49%	≈ 21.49%
Ooxygen	7	15.999	111.993 w ≈ 55.66%	≈ 55.66%
Σ = 201.213 ≈ 201.21 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

O 55.66%

Na 22.85%B 21.49%

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Molar masses of substances nearby

Formula	M, g/mol
NaC₆H₇O₆ (sodium ascorbate)	198.106
CaBr₂ (calcium bromide)	199.886
Hg (mercury)	200.59
Na₂B₄O₇	201.21
C₁₀H₁₈O₄ (sebacic acid)	202.250
C₁₁H₁₂N₂O₂ (tryptophan)	204.229
Tl (thallium)	204.38

FAQ

What is the molar mass of Na2B4O7?

M(Na₂B₄O₇) ≈ 201.21 g/mol

How to calculate the molar mass of Na₂B₄O₇?

Add up the atomic weights of all the atoms in the formula: 2 × 22.990 + 4 × 10.81 + 7 × 15.999 = 201.213 ≈ 201.21 g/mol.

How many grams are in 2 moles of Na₂B₄O₇?

m = n × M = 2 mol × 201.21 g/mol = 402.42 g.

See Also