Molar Mass of Na2B4O7·10H2O
Molar Mass Calculator
What is the molar mass of Na2B4O7·10H2O?
Answer
M(Na2B4O7·10H2O) ≈
381.36 g/mol
Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — B: 10.81.
10 H2O — water of crystallization, part of the molar mass: 10 × 18.015 = 180.150.
Na2B4O7·10H2O = Na2B4O7 + 10 H2O → Na 2, B 4, O 17, H 20
| Element | Atoms, n | Atomic weight, A | n × A, g/mol Mass fraction, w | |
|---|---|---|---|---|
| Nasodium | 2 | 22.990 | 45.980 w ≈ 12.06% | ≈ 12.06% |
| Bboron | 4 | 10.81 | 43.24 w ≈ 11.34% | ≈ 11.34% |
| Ooxygen | 17 | 15.999 | 271.983 w ≈ 71.32% | ≈ 71.32% |
| Hhydrogen | 20 | 1.0080 | 20.1600 w ≈ 5.29% | ≈ 5.29% |
| Σ = 381.363 ≈ 381.36 g/mol w = 100% | 100% | |||
Each fraction is rounded on its own, so the printed ones add up to 100.01%; unrounded, they make exactly 100%.
Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)
O 71.32%
Na 12.06%B 11.34%H 5.29%
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FAQ
What is the molar mass of Na2B4O7·10H2O?
M(Na₂B₄O₇·10H₂O) ≈ 381.36 g/mol
Is the water counted in Na₂B₄O₇·10H₂O?
Yes: the water of crystallization is part of the formula and of the molar mass. 10 H₂O add 10 × 18.015 = 180.150 g/mol; M(Na₂B₄O₇·10H₂O) ≈ 381.36 g/mol, while anhydrous M(Na₂B₄O₇) ≈ 201.21 g/mol.
How many grams are in 2 moles of Na₂B₄O₇·10H₂O?
m = n × M = 2 mol × 381.36 g/mol = 762.72 g.
See Also
- Molar Mass of N (Nitrogen): Step by Step
- Molar Mass of N2 (Nitrogen): Step by Step
- Molar Mass of N2H4 (Hydrazine): Step by Step
- Molar Mass of N2O (Nitrous Oxide): Step by Step
- Molar Mass of N2O3 (Dinitrogen Trioxide): Step by Step
- Molar Mass of N2O4 (Dinitrogen Tetroxide): Step by Step
- Molar Mass of N2O5 (Dinitrogen Pentoxide): Step by Step
- Molar Mass of Nb (Niobium): Step by Step
- Molar Mass of Na (Sodium): Step by Step
- Molar Mass of Na2B4O7: Step by Step
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- Molar Mass of Na2O (Sodium Oxide): Step by Step
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- Molar Mass of Na2SiO3 (Sodium Metasilicate): Step by Step
- Молярная масса Na2B4O7·10H2O: расчёт
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