Molar Mass of Mg(NO3)2 (Magnesium Nitrate)

Molar Mass Calculator

What is the molar mass of Mg(NO₃)₂?

Answer

M(Mg(NO₃)₂) =

148.313 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024).

Mg(NO₃)₂ = Mg + 2 × (N + 3 O) → Mg 1, N 2, O 6

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Mgmagnesium	1	24.305	24.305 w ≈ 16.39%	≈ 16.39%
Nnitrogen	2	14.007	28.014 w ≈ 18.89%	≈ 18.89%
Ooxygen	6	15.999	95.994 w ≈ 64.72%	≈ 64.72%
Σ = 148.313 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

O 64.72%

N 18.89%Mg 16.39%

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Molar masses of substances nearby

Formula	M, g/mol
SrCO₃ (strontium carbonate)	147.63
C₈H₄O₃ (phthalic anhydride)	148.117
C₉H₈O₂ ((E)-cinnamic acid)	148.161
Mg(NO₃)₂ (magnesium nitrate)	148.313
C₅H₁₁NO₂S (DL-methionine)	149.21
AgOCN (silver cyanate)	149.89
NaI (sodium iodide)	149.89

FAQ

What is the molar mass of Mg(NO3)2?

M(Mg(NO₃)₂) = 148.313 g/mol

How to calculate the molar mass of Mg(NO₃)₂?

Add up the atomic weights of all the atoms in the formula: 24.305 + 2 × 14.007 + 6 × 15.999 = 148.313 g/mol.

How many grams are in 2 moles of Mg(NO₃)₂?

m = n × M = 2 mol × 148.313 g/mol = 296.626 g.

See Also