Molar Mass of C9H13NO3 (Epinephrine)

Molar Mass Calculator

What is the molar mass of C₉H₁₃NO₃?

Answer

M(C₉H₁₃NO₃) =

183.207 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024).

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Ccarbon	9	12.011	108.099 w ≈ 59.00%	≈ 59.00%
Hhydrogen	13	1.0080	13.1040 w ≈ 7.15%	≈ 7.15%
Nnitrogen	1	14.007	14.007 w ≈ 7.65%	≈ 7.65%
Ooxygen	3	15.999	47.997 w ≈ 26.20%	≈ 26.20%
Σ = 183.207 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

C 59.00%

O 26.20%N 7.65%H 7.15%

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Molar masses of substances nearby

Formula	M, g/mol
Cl₂O₇ (chlorine heptoxide)	182.89
Co(NO₃)₂ (cobalt(II) nitrate)	182.941
C₇H₅NO₃S (saccharin)	183.18
C₉H₁₃NO₃ (epinephrine)	183.207
(CH₃COO)₂Zn (zinc acetate)	183.47
CuFeS₂	183.51
SrSO₄ (strontium sulfate)	183.68

FAQ

What is the molar mass of C9H13NO3?

M(C₉H₁₃NO₃) = 183.207 g/mol

How to calculate the molar mass of C₉H₁₃NO₃?

Add up the atomic weights of all the atoms in the formula: 9 × 12.011 + 13 × 1.0080 + 14.007 + 3 × 15.999 = 183.207 g/mol.

How many grams are in 2 moles of C₉H₁₃NO₃?

m = n × M = 2 mol × 183.207 g/mol = 366.414 g.

See Also