Molar Mass of C27H28Br2O5S (Bromthymol Blue)

Molar Mass Calculator

What is the molar mass of C₂₇H₂₈Br₂O₅S?

Answer

M(C₂₇H₂₈Br₂O₅S) ≈

624.38 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — S: 32.06.

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Ccarbon	27	12.011	324.297 w ≈ 51.94%	≈ 51.94%
Hhydrogen	28	1.0080	28.2240 w ≈ 4.52%	≈ 4.52%
Brbromine	2	79.904	159.808 w ≈ 25.59%	≈ 25.59%
Ooxygen	5	15.999	79.995 w ≈ 12.81%	≈ 12.81%
Ssulfur	1	32.06	32.06 w ≈ 5.13%	≈ 5.13%
Σ = 624.384 ≈ 624.38 g/mol w = 100%				100%

Each fraction is rounded on its own, so the printed ones add up to 99.99%; unrounded, they make exactly 100%.

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

C 51.94%

Br 25.59%O 12.81%S 5.13%H 4.52%

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Molar masses of substances nearby

Formula	M, g/mol
C₁₂H₂₂CaO₁₄ (calcium gluconate)	430.372
HgI₂ (mercury(II) iodide)	454.39
PbI₂ (lead(II) iodide)	461.0
C₁₆H₉N₄Na₃O₉S₂ (tartrazine)	534.36
Ba₃(PO₄)₂ (barium phosphate)	601.93
C₂₇H₂₈Br₂O₅S (bromthymol blue)	624.38
C₅₇H₁₁₀O₆ (glyceryl tristearate)	891.501

FAQ

What is the molar mass of C27H28Br2O5S?

M(C₂₇H₂₈Br₂O₅S) ≈ 624.38 g/mol

How to calculate the molar mass of C₂₇H₂₈Br₂O₅S?

Add up the atomic weights of all the atoms in the formula: 27 × 12.011 + 28 × 1.0080 + 2 × 79.904 + 5 × 15.999 + 32.06 = 624.384 ≈ 624.38 g/mol.

How many grams are in 2 moles of C₂₇H₂₈Br₂O₅S?

m = n × M = 2 mol × 624.38 g/mol = 1,248.76 g.

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