Molar Mass of C10H14N2 ((−)-nicotine)

Molar Mass Calculator

What is the molar mass of C₁₀H₁₄N₂?

Answer

M(C₁₀H₁₄N₂) =

162.236 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024).

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Ccarbon	10	12.011	120.110 w ≈ 74.03%	≈ 74.03%
Hhydrogen	14	1.0080	14.1120 w ≈ 8.70%	≈ 8.70%
Nnitrogen	2	14.007	28.014 w ≈ 17.27%	≈ 17.27%
Σ = 162.236 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

C 74.03%

N 17.27%H 8.70%

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Molar masses of substances nearby

Formula	M, g/mol
Na₂CrO₄ (sodium chromate)	161.972
Ca(HCO₃)₂ (calcium bicarbonate)	162.110
FeCl₃ (ferric chloride)	162.20
C₁₀H₁₄N₂ ((−)-nicotine)	162.236
C₆H₁₀OS₂ (allicin)	162.27
Dy (dysprosium)	162.50
Na₃PO₄ (trisodium phosphate)	163.940

FAQ

What is the molar mass of C10H14N2?

M(C₁₀H₁₄N₂) = 162.236 g/mol

How to calculate the molar mass of C₁₀H₁₄N₂?

Add up the atomic weights of all the atoms in the formula: 10 × 12.011 + 14 × 1.0080 + 2 × 14.007 = 162.236 g/mol.

How many grams are in 2 moles of C₁₀H₁₄N₂?

m = n × M = 2 mol × 162.236 g/mol = 324.472 g.

See Also