Molar Mass of BaI2 (Barium Iodide)

Molar Mass Calculator

What is the molar mass of BaI₂?

Answer

M(BaI₂) =

391.13 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024).

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Babarium	1	137.33	137.33 w ≈ 35.11%	≈ 35.11%
Iiodine	2	126.90	253.80 w ≈ 64.89%	≈ 64.89%
Σ = 391.13 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

I 64.89%Ba 35.11%

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Molar masses of substances nearby

Formula	M, g/mol
AgC₁₀H₉N₄SO₂	357.14
Na₂B₄O₇·10H₂O	381.36
Zn₃(PO₄)₂ (zinc phosphate)	386.08
BaI₂ (barium iodide)	391.13
Cr₂(SO₄)₃ (chromium(III) sulfate)	392.16
CHI₃ (iodoform)	393.72
C₁₂H₁₉Cl₃O₈ (sucralose)	397.63

FAQ

What is the molar mass of BaI2?

M(BaI₂) = 391.13 g/mol

How to calculate the molar mass of BaI₂?

Add up the atomic weights of all the atoms in the formula: 137.33 + 2 × 126.90 = 391.13 g/mol.

How many grams are in 2 moles of BaI₂?

m = n × M = 2 mol × 391.13 g/mol = 782.26 g.

See Also