Molar Mass of BaCrO4 (Barium Chromate)

Molar Mass Calculator

What is the molar mass of BaCrO₄?

Answer

M(BaCrO₄) ≈

253.32 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — Ba: 137.33.

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Babarium	1	137.33	137.33 w ≈ 54.21%	≈ 54.21%
Crchromium	1	51.996	51.996 w ≈ 20.53%	≈ 20.53%
Ooxygen	4	15.999	63.996 w ≈ 25.26%	≈ 25.26%
Σ = 253.322 ≈ 253.32 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

Ba 54.21%

O 25.26%Cr 20.53%

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Molar masses of substances nearby

Formula	M, g/mol
Ag₂S (silver sulfide)	247.80
CuSO₄·5H₂O (copper(II) sulfate pentahydrate)	249.68
(NH₄)₂Cr₂O₇ (ammonium dichromate)	252.063
BaCrO₄ (barium chromate)	253.32
I₂ (iodine)	253.80
S₈ (octasulfur)	256.48
C₆H₅Na₃O₇ (trisodium citrate)	258.069

FAQ

What is the molar mass of BaCrO4?

M(BaCrO₄) ≈ 253.32 g/mol

How to calculate the molar mass of BaCrO₄?

Add up the atomic weights of all the atoms in the formula: 137.33 + 51.996 + 4 × 15.999 = 253.322 ≈ 253.32 g/mol.

How many grams are in 2 moles of BaCrO₄?

m = n × M = 2 mol × 253.32 g/mol = 506.64 g.

See Also