Molar Mass of AlBr3 (Aluminum Bromide)

Molar Mass Calculator

What is the molar mass of AlBr₃?

Answer

M(AlBr₃) =

266.694 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024).

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Alaluminium	1	26.982	26.982 w ≈ 10.12%	≈ 10.12%
Brbromine	3	79.904	239.712 w ≈ 89.88%	≈ 89.88%
Σ = 266.694 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

Br 89.88%

Al 10.12%

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Molar masses of substances nearby

Formula	M, g/mol
Ba(NO₃)₂ (barium nitrate)	261.34
Na₂Cr₂O₇ (sodium dichromate)	261.965
Mg₃(PO₄)₂ (magnesium phosphate)	262.855
AlBr₃ (aluminum bromide)	266.694
PbCO₃ (lead carbonate)	267.2
HgCl₂ (mercuric chloride)	271.49
Ag₂CO₃ (silver carbonate)	275.75

FAQ

What is the molar mass of AlBr3?

M(AlBr₃) = 266.694 g/mol

How to calculate the molar mass of AlBr₃?

Add up the atomic weights of all the atoms in the formula: 26.982 + 3 × 79.904 = 266.694 g/mol.

How many grams are in 2 moles of AlBr₃?

m = n × M = 2 mol × 266.694 g/mol = 533.388 g.

See Also