Cube Root of 1738

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What is the cube root of 1,738?

Answer

∛1,738 ≈
12.0231

Real cube root: the only number whose cube is 1,738.

≈ — rounded to 4 decimal places. 1,738 is not the cube of a rational number, so ∛1,738 is irrational: its decimal expansion never ends and never repeats.

Prime factors
1,738 = 2 × 11 × 79
Take out of the root
No prime appears three times, so ∛1,738 is already in simplest form.
Between cubes
12³ = 1,728 < 1,738 < 2,197 = 13³, so 12 < ∛1,738 < 13 and ∛1,738 ≈ 12.0231

See Also

Recalculate with different values ↑

Cube roots of nearby values

N∛N
1,726≈ 11.9954
1,72812
1,729≈ 12.0023
1,738≈ 12.0231
1,8002∛225 ≈ 12.1644
2,00010∛2 ≈ 12.5992
2,007≈ 12.6139

FAQ

What is the cube root of 1,738?

∛1,738 ≈ 12.0231

Can ∛1,738 be simplified?

No: no prime appears three times in 1,738, so its only cube factor is 1 and ∛1,738 is already in simplest form. Since 12³ = 1,728 < 1,738 < 2,197 = 13³, ∛1,738 lies between 12 and 13: ∛1,738 ≈ 12.0231.

Is ∛1,738 a rational number?

No: 1,738 is not the cube of a rational number, and the cube root of a fraction p/q in lowest terms is rational only when p and q are both cubes. So ∛1,738 is irrational; its decimal never ends and never repeats: ∛1,738 ≈ 12.0231.

See Also