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    Cube Root of 1726

    Cube Root Calculator
    Cube root of

    What is the cube root of 1,726?

    Answer

    ∛1,726 ≈
    11.9954

    Real cube root: the only number whose cube is 1,726.

    ≈ — rounded to 4 decimal places. 1,726 is not the cube of a rational number, so ∛1,726 is irrational: its decimal expansion never ends and never repeats.

    Prime factors
    1,726 = 2 × 863
    Take out of the root
    No prime appears three times, so ∛1,726 is already in simplest form.
    Between cubes
    11³ = 1,331 < 1,726 < 1,728 = 12³, so 11 < ∛1,726 < 12 and ∛1,726 ≈ 11.9954

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    https://calculat.io/en/number/cube-root/1726Copy
    <a href="https://calculat.io/en/number/cube-root/1726">Cube Root of 1726 (∛1726): Exact Value and Decimal</a>Copy
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    Cube Root of 1726 (∛1726): Exact Value and Decimal. ∛1,726 ≈ 11.9954. 1,726 has no cube factor but 1, so ∛1,726 is already simplest; it lies between 11 and 12.
    https://calculat.io/en/number/cube-root/1726/generated.jpgCopy

    Cube roots of nearby values

    N∛N
    1,7013∛63 ≈ 11.9372
    1,7157∛5 ≈ 11.9698
    1,725≈ 11.9931
    1,726≈ 11.9954
    1,72812
    1,729≈ 12.0023
    1,738≈ 12.0231
    Recalculate with different values ↑

    FAQ

    What is the cube root of 1,726?

    ∛1,726 ≈ 11.9954

    Can ∛1,726 be simplified?

    No: no prime appears three times in 1,726, so its only cube factor is 1 and ∛1,726 is already in simplest form. Since 11³ = 1,331 < 1,726 < 1,728 = 12³, ∛1,726 lies between 11 and 12: ∛1,726 ≈ 11.9954.

    Is ∛1,726 a rational number?

    No: 1,726 is not the cube of a rational number, and the cube root of a fraction p/q in lowest terms is rational only when p and q are both cubes. So ∛1,726 is irrational; its decimal never ends and never repeats: ∛1,726 ≈ 11.9954.

    See Also