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    Cube Root of 1738

    Cube Root Calculator
    Cube root of

    What is the cube root of 1,738?

    Answer

    ∛1,738 ≈
    12.0231

    Real cube root: the only number whose cube is 1,738.

    ≈ — rounded to 4 decimal places. 1,738 is not the cube of a rational number, so ∛1,738 is irrational: its decimal expansion never ends and never repeats.

    Prime factors
    1,738 = 2 × 11 × 79
    Take out of the root
    No prime appears three times, so ∛1,738 is already in simplest form.
    Between cubes
    12³ = 1,728 < 1,738 < 2,197 = 13³, so 12 < ∛1,738 < 13 and ∛1,738 ≈ 12.0231

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    https://calculat.io/en/number/cube-root/1738Copy
    <a href="https://calculat.io/en/number/cube-root/1738">Cube Root of 1738 (∛1738): Exact Value and Decimal</a>Copy
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    Cube Root of 1738 (∛1738): Exact Value and Decimal. ∛1,738 ≈ 12.0231. 1,738 has no cube factor but 1, so ∛1,738 is already simplest; it lies between 12 and 13.
    https://calculat.io/en/number/cube-root/1738/generated.jpgCopy

    Cube roots of nearby values

    N∛N
    1,726≈ 11.9954
    1,72812
    1,729≈ 12.0023
    1,738≈ 12.0231
    1,8002∛225 ≈ 12.1644
    2,00010∛2 ≈ 12.5992
    2,007≈ 12.6139
    Recalculate with different values ↑

    FAQ

    What is the cube root of 1,738?

    ∛1,738 ≈ 12.0231

    Can ∛1,738 be simplified?

    No: no prime appears three times in 1,738, so its only cube factor is 1 and ∛1,738 is already in simplest form. Since 12³ = 1,728 < 1,738 < 2,197 = 13³, ∛1,738 lies between 12 and 13: ∛1,738 ≈ 12.0231.

    Is ∛1,738 a rational number?

    No: 1,738 is not the cube of a rational number, and the cube root of a fraction p/q in lowest terms is rational only when p and q are both cubes. So ∛1,738 is irrational; its decimal never ends and never repeats: ∛1,738 ≈ 12.0231.

    See Also