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    Cube Root of 2300

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    Cube root of

    What is the cube root of 2,300?

    Answer

    ∛2,300 ≈
    13.2001

    Real cube root: the only number whose cube is 2,300.

    ≈ — rounded to 4 decimal places. 2,300 is not the cube of a rational number, so ∛2,300 is irrational: its decimal expansion never ends and never repeats.

    Prime factors
    2,300 = 2 × 2 × 5 × 5 × 23 = 2² × 5² × 23
    Take out of the root
    No prime appears three times, so ∛2,300 is already in simplest form.
    Between cubes
    13³ = 2,197 < 2,300 < 2,744 = 14³, so 13 < ∛2,300 < 14 and ∛2,300 ≈ 13.2001

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    https://calculat.io/en/number/cube-root/2300Copy
    <a href="https://calculat.io/en/number/cube-root/2300">Cube Root of 2300 (∛2300): Exact Value and Decimal</a>Copy
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    Cube Root of 2300 (∛2300): Exact Value and Decimal. ∛2,300 ≈ 13.2001. 2,300 has no cube factor but 1, so ∛2,300 is already simplest; it lies between 13 and 14.
    https://calculat.io/en/number/cube-root/2300/generated.jpgCopy

    Cube roots of nearby values

    N∛N
    2,0242∛253 ≈ 12.6494
    2,19713
    2,2002∛275 ≈ 13.0059
    2,300≈ 13.2001
    2,4002∛300 ≈ 13.3887
    2,4017∛7 ≈ 13.3905
    2,450≈ 13.481
    Recalculate with different values ↑

    FAQ

    What is the cube root of 2,300?

    ∛2,300 ≈ 13.2001

    Can ∛2,300 be simplified?

    No: no prime appears three times in 2,300, so its only cube factor is 1 and ∛2,300 is already in simplest form. Since 13³ = 2,197 < 2,300 < 2,744 = 14³, ∛2,300 lies between 13 and 14: ∛2,300 ≈ 13.2001.

    Is ∛2,300 a rational number?

    No: 2,300 is not the cube of a rational number, and the cube root of a fraction p/q in lowest terms is rational only when p and q are both cubes. So ∛2,300 is irrational; its decimal never ends and never repeats: ∛2,300 ≈ 13.2001.

    See Also