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    Cube Root of 1729

    Cube Root Calculator
    Cube root of

    What is the cube root of 1,729?

    Answer

    ∛1,729 ≈
    12.0023

    Real cube root: the only number whose cube is 1,729.

    ≈ — rounded to 4 decimal places. 1,729 is not the cube of a rational number, so ∛1,729 is irrational: its decimal expansion never ends and never repeats.

    Prime factors
    1,729 = 7 × 13 × 19
    Take out of the root
    No prime appears three times, so ∛1,729 is already in simplest form.
    Between cubes
    12³ = 1,728 < 1,729 < 2,197 = 13³, so 12 < ∛1,729 < 13 and ∛1,729 ≈ 12.0023

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    https://calculat.io/en/number/cube-root/1729Copy
    <a href="https://calculat.io/en/number/cube-root/1729">Cube Root of 1729 (∛1729): Exact Value and Decimal</a>Copy
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    Cube Root of 1729 (∛1729): Exact Value and Decimal. ∛1,729 ≈ 12.0023. 1,729 has no cube factor but 1, so ∛1,729 is already simplest; it lies between 12 and 13.
    https://calculat.io/en/number/cube-root/1729/generated.jpgCopy

    Cube roots of nearby values

    N∛N
    1,725≈ 11.9931
    1,726≈ 11.9954
    1,72812
    1,729≈ 12.0023
    1,738≈ 12.0231
    1,8002∛225 ≈ 12.1644
    2,00010∛2 ≈ 12.5992
    Recalculate with different values ↑

    FAQ

    What is the cube root of 1,729?

    ∛1,729 ≈ 12.0023

    Can ∛1,729 be simplified?

    No: no prime appears three times in 1,729, so its only cube factor is 1 and ∛1,729 is already in simplest form. Since 12³ = 1,728 < 1,729 < 2,197 = 13³, ∛1,729 lies between 12 and 13: ∛1,729 ≈ 12.0023.

    Is ∛1,729 a rational number?

    No: 1,729 is not the cube of a rational number, and the cube root of a fraction p/q in lowest terms is rational only when p and q are both cubes. So ∛1,729 is irrational; its decimal never ends and never repeats: ∛1,729 ≈ 12.0023.

    See Also