Molar Mass of NaNO3 (Sodium Nitrate)

Molar Mass Calculator

What is the molar mass of NaNO₃?

Answer

M(NaNO₃) =

84.994 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024).

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Nasodium	1	22.990	22.990 w ≈ 27.05%	≈ 27.05%
Nnitrogen	1	14.007	14.007 w ≈ 16.48%	≈ 16.48%
Ooxygen	3	15.999	47.997 w ≈ 56.47%	≈ 56.47%
Σ = 84.994 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

O 56.47%

Na 27.05%N 16.48%

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Molar masses of substances nearby

Formula	M, g/mol
MgCO₃ (magnesium carbonate)	84.313
HClO₃ (chloric acid)	84.46
CH₂Cl₂ (dichloromethane)	84.93
NaNO₃ (sodium nitrate)	84.994
KNO₂ (potassium nitrite)	85.103
Rb (rubidium)	85.468
C₄H₆O₂ (methacrylic acid)	86.090

FAQ

What is the molar mass of NaNO3?

M(NaNO₃) = 84.994 g/mol

How to calculate the molar mass of NaNO₃?

Add up the atomic weights of all the atoms in the formula: 22.990 + 14.007 + 3 × 15.999 = 84.994 g/mol.

How many grams are in 2 moles of NaNO₃?

m = n × M = 2 mol × 84.994 g/mol = 169.988 g.

See Also