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    Molar Mass of NaH2PO4 (Monosodium Phosphate)

    Molar Mass Calculator
    Chemical formula

    What is the molar mass of NaH2PO4?

    Answer

    M(NaH2PO4) =
    119.976 g/mol

    Atomic weights: IUPAC standard values (CIAAW, 2024).

    Contribution of each element
    Element Atoms, n Atomic weight, A n × A, g/mol Mass fraction, w
    Nasodium122.99022.990 w ≈ 19.16%
    Hhydrogen21.00802.0160 w ≈ 1.68%
    Pphosphorus130.97430.974 w ≈ 25.82%
    Ooxygen415.99963.996 w ≈ 53.34%
    Σ = 119.976 g/mol w = 100%

    Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

    Mass fractions of the elements

    P 25.82%Na 19.16%H 1.68%

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    Molar Mass of NaH2PO4 (Monosodium Phosphate): Step by Step. M(NaH2PO4) = 119.976 g/mol: 22.990 (Na) + 2 × 1.0080 (H) + 30.974 (P) + 4 × 15.999 (O). Mass fractions: O 53.34%, P 25.82%, Na 19.16%.
    https://calculat.io/en/other/molar-mass/nah2po4/generated.jpgCopy

    FAQ

    What is the molar mass of NaH2PO4?

    M(NaH₂PO₄) = 119.976 g/mol

    How to calculate the molar mass of NaH₂PO₄?

    Add up the atomic weights of all the atoms in the formula: 22.990 + 2 × 1.0080 + 30.974 + 4 × 15.999 = 119.976 g/mol.

    How many grams are in 2 moles of NaH₂PO₄?

    m = n × M = 2 mol × 119.976 g/mol = 239.952 g.