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    Molar Mass of NH4H2PO4 (Monobasic Ammonium Phosphate)

    Molar Mass Calculator
    Chemical formula

    What is the molar mass of NH4H2PO4?

    Answer

    M(NH4H2PO4) =
    115.025 g/mol

    Atomic weights: IUPAC standard values (CIAAW, 2024).

    Contribution of each element
    Element Atoms, n Atomic weight, A n × A, g/mol Mass fraction, w
    Nnitrogen114.00714.007 w ≈ 12.18%
    Hhydrogen61.00806.0480 w ≈ 5.26%
    Pphosphorus130.97430.974 w ≈ 26.93%
    Ooxygen415.99963.996 w ≈ 55.64%
    Σ = 115.025 g/mol w = 100%

    Each fraction is rounded on its own, so the printed ones add up to 100.01%; unrounded, they make exactly 100%.

    Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

    Mass fractions of the elements

    P 26.93%N 12.18%H 5.26%

    See Also

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    Molar Mass of NH4H2PO4 (Monobasic Ammonium Phosphate). M(NH4H2PO4) = 115.025 g/mol: 14.007 (N) + 6 × 1.0080 (H) + 30.974 (P) + 4 × 15.999 (O). Mass fractions: O 55.64%, P 26.93%, N 12.18%.
    https://calculat.io/en/other/molar-mass/nh4h2po4/generated.jpgCopy

    FAQ

    What is the molar mass of NH4H2PO4?

    M(NH₄H₂PO₄) = 115.025 g/mol

    How to calculate the molar mass of NH₄H₂PO₄?

    Add up the atomic weights of all the atoms in the formula: 14.007 + 6 × 1.0080 + 30.974 + 4 × 15.999 = 115.025 g/mol.

    How many grams are in 2 moles of NH₄H₂PO₄?

    m = n × M = 2 mol × 115.025 g/mol = 230.050 g.