Molar Mass of NaNO2 (Sodium Nitrite)

Molar Mass Calculator

What is the molar mass of NaNO₂?

Answer

M(NaNO₂) =

68.995 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024).

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Nasodium	1	22.990	22.990 w ≈ 33.32%	≈ 33.32%
Nnitrogen	1	14.007	14.007 w ≈ 20.30%	≈ 20.30%
Ooxygen	2	15.999	31.998 w ≈ 46.38%	≈ 46.38%
Σ = 68.995 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

O 46.38%

Na 33.32%N 20.30%

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Molar masses of substances nearby

Formula	M, g/mol
C₃H₄N₂ (imidazole)	68.079
(NH₄)₂S (ammonium sulfide)	68.14
LiNO₃ (lithium nitrate)	68.94
NaNO₂ (sodium nitrite)	68.995
B₂O₃ (diboron trioxide)	69.62
Ga (gallium)	69.723
C₅H₁₀ (cyclopentane)	70.135

FAQ

What is the molar mass of NaNO2?

M(NaNO₂) = 68.995 g/mol

How to calculate the molar mass of NaNO₂?

Add up the atomic weights of all the atoms in the formula: 22.990 + 14.007 + 2 × 15.999 = 68.995 g/mol.

How many grams are in 2 moles of NaNO₂?

m = n × M = 2 mol × 68.995 g/mol = 137.990 g.

See Also