Molar Mass of C6H5Na3O7 (Trisodium Citrate)

Molar Mass Calculator

What is the molar mass of C₆H₅Na₃O₇?

Answer

M(C₆H₅Na₃O₇) =

258.069 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024).

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Ccarbon	6	12.011	72.066 w ≈ 27.93%	≈ 27.93%
Hhydrogen	5	1.0080	5.0400 w ≈ 1.95%	≈ 1.95%
Nasodium	3	22.990	68.970 w ≈ 26.73%	≈ 26.73%
Ooxygen	7	15.999	111.993 w ≈ 43.40%	≈ 43.40%
Σ = 258.069 g/mol w = 100%				100%

Each fraction is rounded on its own, so the printed ones add up to 100.01%; unrounded, they make exactly 100%.

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

O 43.40%

C 27.93%Na 26.73%H 1.95%

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Molar masses of substances nearby

Formula	M, g/mol
BaCrO₄ (barium chromate)	253.32
I₂ (iodine)	253.80
S₈ (octasulfur)	256.48
C₆H₅Na₃O₇ (trisodium citrate)	258.069
Ba(NO₃)₂ (barium nitrate)	261.34
Na₂Cr₂O₇ (sodium dichromate)	261.965
Mg₃(PO₄)₂ (magnesium phosphate)	262.855

FAQ

What is the molar mass of C6H5Na3O7?

M(C₆H₅Na₃O₇) = 258.069 g/mol

How to calculate the molar mass of C₆H₅Na₃O₇?

Add up the atomic weights of all the atoms in the formula: 6 × 12.011 + 5 × 1.0080 + 3 × 22.990 + 7 × 15.999 = 258.069 g/mol.

How many grams are in 2 moles of C₆H₅Na₃O₇?

m = n × M = 2 mol × 258.069 g/mol = 516.138 g.

See Also