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    Molar Mass of C6H7NO3S (Sulfanilic Acid)

    Molar Mass Calculator
    Chemical formula

    What is the molar mass of C6H7NO3S?

    Answer

    M(C6H7NO3S) ≈
    173.19 g/mol

    Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — S: 32.06.

    Contribution of each element
    Element Atoms, n Atomic weight, A n × A, g/mol Mass fraction, w
    Ccarbon612.01172.066 w ≈ 41.61%
    Hhydrogen71.00807.0560 w ≈ 4.07%
    Nnitrogen114.00714.007 w ≈ 8.09%
    Ooxygen315.99947.997 w ≈ 27.71%
    Ssulfur132.0632.06 w ≈ 18.51%
    Σ = 173.186 ≈ 173.19 g/mol w = 100%

    Each fraction is rounded on its own, so the printed ones add up to 99.99%; unrounded, they make exactly 100%.

    Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

    Mass fractions of the elements

    O 27.71%S 18.51%N 8.09%H 4.07%

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    <a href="https://calculat.io/en/other/molar-mass/c6h7no3s">Molar Mass of C6H7NO3S (Sulfanilic Acid): Step by Step</a>Copy
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    Molar Mass of C6H7NO3S (Sulfanilic Acid): Step by Step. M(C6H7NO3S) ≈ 173.19 g/mol: 6 × 12.011 (C) + 7 × 1.0080 (H) + 14.007 (N) + 3 × 15.999 (O) + 32.06 (S). Mass fractions: C 41.61%, O 27.71%, S 18.51%.
    https://calculat.io/en/other/molar-mass/c6h7no3s/generated.jpgCopy

    FAQ

    What is the molar mass of C6H7NO3S?

    M(C₆H₇NO₃S) ≈ 173.19 g/mol

    How to calculate the molar mass of C₆H₇NO₃S?

    Add up the atomic weights of all the atoms in the formula: 6 × 12.011 + 7 × 1.0080 + 14.007 + 3 × 15.999 + 32.06 = 173.186 ≈ 173.19 g/mol.

    How many grams are in 2 moles of C₆H₇NO₃S?

    m = n × M = 2 mol × 173.19 g/mol = 346.38 g.