Molar Mass of Al(NO3)3 (Aluminum Nitrate)

Molar Mass Calculator

What is the molar mass of Al(NO₃)₃?

Answer

M(Al(NO₃)₃) =

212.994 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024).

Al(NO₃)₃ = Al + 3 × (N + 3 O) → Al 1, N 3, O 9

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Alaluminium	1	26.982	26.982 w ≈ 12.67%	≈ 12.67%
Nnitrogen	3	14.007	42.021 w ≈ 19.73%	≈ 19.73%
Ooxygen	9	15.999	143.991 w ≈ 67.60%	≈ 67.60%
Σ = 212.994 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

O 67.60%

N 19.73%Al 12.67%

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Molar masses of substances nearby

Formula	M, g/mol
Bi (bismuth)	208.98
Sr(NO₃)₂ (strontium nitrate)	211.63
K₃PO₄ (tribasic potassium phosphate)	212.264
Al(NO₃)₃ (aluminum nitrate)	212.994
KIO₃ (potassium iodate)	214.00
HgO (mercury(II) oxide)	216.59
Mn₂O₇ (manganese heptoxide)	221.869

FAQ

What is the molar mass of Al(NO3)3?

M(Al(NO₃)₃) = 212.994 g/mol

How to calculate the molar mass of Al(NO₃)₃?

Add up the atomic weights of all the atoms in the formula: 26.982 + 3 × 14.007 + 9 × 15.999 = 212.994 g/mol.

How many grams are in 2 moles of Al(NO₃)₃?

m = n × M = 2 mol × 212.994 g/mol = 425.988 g.

See Also