Molar Mass of Sr(NO3)2 (Strontium Nitrate)
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What is the molar mass of Sr(NO3)2?
Answer
M(Sr(NO3)2) ≈
211.63 g/mol
Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — Sr: 87.62.
Sr(NO3)2 = Sr + 2 × (N + 3 O) → Sr 1, N 2, O 6
| Element | Atoms, n | Atomic weight, A | n × A, g/mol Mass fraction, w | |
|---|---|---|---|---|
| Srstrontium | 1 | 87.62 | 87.62 w ≈ 41.40% | ≈ 41.40% |
| Nnitrogen | 2 | 14.007 | 28.014 w ≈ 13.24% | ≈ 13.24% |
| Ooxygen | 6 | 15.999 | 95.994 w ≈ 45.36% | ≈ 45.36% |
| Σ = 211.628 ≈ 211.63 g/mol w = 100% | 100% | |||
Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)
O 45.36%Sr 41.40%
N 13.24%
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Molar masses of substances nearby
| Formula | M, g/mol |
|---|---|
| PCl₅ (phosphorus pentachloride) | 208.22 |
| BaCl₂ (barium chloride) | 208.23 |
| Bi (bismuth) | 208.98 |
| Sr(NO₃)₂ (strontium nitrate) | 211.63 |
| K₃PO₄ (tribasic potassium phosphate) | 212.264 |
| Al(NO₃)₃ (aluminum nitrate) | 212.994 |
| KIO₃ (potassium iodate) | 214.00 |