Molar Mass of AgI (Silver Iodide)
Molar Mass Calculator
What is the molar mass of AgI?
Answer
M(AgI) =
234.77 g/mol
Atomic weights: IUPAC standard values (CIAAW, 2024).
| Element | Atoms, n | Atomic weight, A | n × A, g/mol Mass fraction, w | |
|---|---|---|---|---|
| Agsilver | 1 | 107.87 | 107.87 w ≈ 45.95% | ≈ 45.95% |
| Iiodine | 1 | 126.90 | 126.90 w ≈ 54.05% | ≈ 54.05% |
| Σ = 234.77 g/mol w = 100% | 100% | |||
Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)
I 54.05%Ag 45.95%
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FAQ
What is the molar mass of AgI?
M(AgI) = 234.77 g/mol
How to calculate the molar mass of AgI?
Add up the atomic weights of all the atoms in the formula: 107.87 + 126.90 = 234.77 g/mol.
How many grams are in 2 moles of AgI?
m = n × M = 2 mol × 234.77 g/mol = 469.54 g.
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