Molar Mass of Ca(H2PO4)2 (Monocalcium Phosphate)
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What is the molar mass of Ca(H2PO4)2?
Answer
M(Ca(H2PO4)2) =
234.050 g/mol
Atomic weights: IUPAC standard values (CIAAW, 2024).
Ca(H2PO4)2 = Ca + 2 × (2 H + P + 4 O) → Ca 1, H 4, P 2, O 8
| Element | Atoms, n | Atomic weight, A | n × A, g/mol Mass fraction, w | |
|---|---|---|---|---|
| Cacalcium | 1 | 40.078 | 40.078 w ≈ 17.12% | ≈ 17.12% |
| Hhydrogen | 4 | 1.0080 | 4.0320 w ≈ 1.72% | ≈ 1.72% |
| Pphosphorus | 2 | 30.974 | 61.948 w ≈ 26.47% | ≈ 26.47% |
| Ooxygen | 8 | 15.999 | 127.992 w ≈ 54.69% | ≈ 54.69% |
| Σ = 234.050 g/mol w = 100% | 100% | |||
Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)
O 54.69%
P 26.47%Ca 17.12%H 1.72%
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Molar masses of substances nearby
| Formula | M, g/mol |
|---|---|
| Th (thorium) | 232.04 |
| HgS (mercury(II) sulfide) | 232.65 |
| BaSO₄ (barium sulfate) | 233.39 |
| Ca(H₂PO₄)₂ (monocalcium phosphate) | 234.050 |
| AgI (silver iodide) | 234.77 |
| CdN₂O₆ (cadmium nitrate) | 236.42 |
| U (uranium) | 238.03 |