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What is the cube root of 1,725?

Answer

∛1,725 ≈
11.9931

Real cube root: the only number whose cube is 1,725.

≈ — rounded to 4 decimal places. 1,725 is not the cube of a rational number, so ∛1,725 is irrational: its decimal expansion never ends and never repeats.

Prime factors
1,725 = 3 × 5 × 5 × 23 = 3 × 5² × 23
Take out of the root
No prime appears three times, so ∛1,725 is already in simplest form.
Between cubes
11³ = 1,331 < 1,725 < 1,728 = 12³, so 11 < ∛1,725 < 12 and ∛1,725 ≈ 11.9931

Related Calculations

See Also

Recalculate with different values ↑

Cube roots of nearby values

N∛N
1,700≈ 11.9348
1,7013∛63 ≈ 11.9372
1,7157∛5 ≈ 11.9698
1,725≈ 11.9931
1,726≈ 11.9954
1,72812
1,729≈ 12.0023

FAQ

What is the cube root of 1,725?

∛1,725 ≈ 11.9931

Can ∛1,725 be simplified?

No: no prime appears three times in 1,725, so its only cube factor is 1 and ∛1,725 is already in simplest form. Since 11³ = 1,331 < 1,725 < 1,728 = 12³, ∛1,725 lies between 11 and 12: ∛1,725 ≈ 11.9931.

Is ∛1,725 a rational number?

No: 1,725 is not the cube of a rational number, and the cube root of a fraction p/q in lowest terms is rational only when p and q are both cubes. So ∛1,725 is irrational; its decimal never ends and never repeats: ∛1,725 ≈ 11.9931.

See Also