Molar Mass of ZnBr2 (Zinc Bromide)

Molar Mass Calculator

What is the molar mass of ZnBr₂?

Answer

M(ZnBr₂) ≈

225.19 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — Zn: 65.38.

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Znzinc	1	65.38	65.38 w ≈ 29.03%	≈ 29.03%
Brbromine	2	79.904	159.808 w ≈ 70.97%	≈ 70.97%
Σ = 225.188 ≈ 225.19 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

Br 70.97%

Zn 29.03%

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Molar masses of substances nearby

Formula	M, g/mol
Mn₂O₇ (manganese heptoxide)	221.869
C₃H₆N₆O₆ (cyclonite)	222.117
PbO (lead(II) oxide)	223.2
ZnBr₂ (zinc bromide)	225.19
C₃H₅N₃O₉ (nitroglycerin)	227.085
C₇H₅N₃O₆ (TNT)	227.132
SbCl₃ (antimony trichloride)	228.11

FAQ

What is the molar mass of ZnBr2?

M(ZnBr₂) ≈ 225.19 g/mol

How to calculate the molar mass of ZnBr₂?

Add up the atomic weights of all the atoms in the formula: 65.38 + 2 × 79.904 = 225.188 ≈ 225.19 g/mol.

How many grams are in 2 moles of ZnBr₂?

m = n × M = 2 mol × 225.19 g/mol = 450.38 g.

See Also