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    Molar Mass of ZnBr2 (Zinc Bromide)

    Molar Mass Calculator
    Chemical formula

    What is the molar mass of ZnBr2?

    Answer

    M(ZnBr2) ≈
    225.19 g/mol

    Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — Zn: 65.38.

    Contribution of each element
    Element Atoms, n Atomic weight, A n × A, g/mol Mass fraction, w
    Znzinc165.3865.38 w ≈ 29.03%
    Brbromine279.904159.808 w ≈ 70.97%
    Σ = 225.188 ≈ 225.19 g/mol w = 100%

    Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

    Mass fractions of the elements

    Zn 29.03%

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    <a href="https://calculat.io/en/other/molar-mass/znbr2">Molar Mass of ZnBr2 (Zinc Bromide): Step by Step</a>Copy
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    Molar Mass of ZnBr2 (Zinc Bromide): Step by Step. M(ZnBr2) ≈ 225.19 g/mol: 65.38 (Zn) + 2 × 79.904 (Br). Mass fractions: Br 70.97%, Zn 29.03%.
    https://calculat.io/en/other/molar-mass/znbr2/generated.jpgCopy

    Molar masses of substances nearby

    FormulaM, g/mol
    Mn₂O₇ (manganese heptoxide)221.869
    C₃H₆N₆O₆ (cyclonite)222.117
    PbO (lead(II) oxide)223.2
    ZnBr₂ (zinc bromide)225.19
    C₃H₅N₃O₉ (nitroglycerin)227.085
    C₇H₅N₃O₆ (TNT)227.132
    SbCl₃ (antimony trichloride)228.11
    Recalculate with different values ↑

    FAQ

    What is the molar mass of ZnBr2?

    M(ZnBr₂) ≈ 225.19 g/mol

    How to calculate the molar mass of ZnBr₂?

    Add up the atomic weights of all the atoms in the formula: 65.38 + 2 × 79.904 = 225.188 ≈ 225.19 g/mol.

    How many grams are in 2 moles of ZnBr₂?

    m = n × M = 2 mol × 225.19 g/mol = 450.38 g.

    See Also