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    Molar Mass of C3H5N3O9 (Nitroglycerin)

    Molar Mass Calculator
    Chemical formula

    What is the molar mass of C3H5N3O9?

    Answer

    M(C3H5N3O9) =
    227.085 g/mol

    Atomic weights: IUPAC standard values (CIAAW, 2024).

    Contribution of each element
    Element Atoms, n Atomic weight, A n × A, g/mol Mass fraction, w
    Ccarbon312.01136.033 w ≈ 15.87%
    Hhydrogen51.00805.0400 w ≈ 2.22%
    Nnitrogen314.00742.021 w ≈ 18.50%
    Ooxygen915.999143.991 w ≈ 63.41%
    Σ = 227.085 g/mol w = 100%

    Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

    Mass fractions of the elements

    N 18.50%C 15.87%H 2.22%

    See Also

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    <a href="https://calculat.io/en/other/molar-mass/c3h5n3o9">Molar Mass of C3H5N3O9 (Nitroglycerin): Step by Step</a>Copy
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    Molar Mass of C3H5N3O9 (Nitroglycerin): Step by Step. M(C3H5N3O9) = 227.085 g/mol: 3 × 12.011 (C) + 5 × 1.0080 (H) + 3 × 14.007 (N) + 9 × 15.999 (O). Mass fractions: O 63.41%, N 18.50%, C 15.87%.
    https://calculat.io/en/other/molar-mass/c3h5n3o9/generated.jpgCopy

    FAQ

    What is the molar mass of C3H5N3O9?

    M(C₃H₅N₃O₉) = 227.085 g/mol

    How to calculate the molar mass of C₃H₅N₃O₉?

    Add up the atomic weights of all the atoms in the formula: 3 × 12.011 + 5 × 1.0080 + 3 × 14.007 + 9 × 15.999 = 227.085 g/mol.

    How many grams are in 2 moles of C₃H₅N₃O₉?

    m = n × M = 2 mol × 227.085 g/mol = 454.170 g.