Molar Mass of Zn3(PO4)2 (Zinc Phosphate)

Molar Mass Calculator

What is the molar mass of Zn₃(PO₄)₂?

Answer

M(Zn₃(PO₄)₂) =

386.08 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024).

Zn₃(PO₄)₂ = 3 Zn + 2 × (P + 4 O) → Zn 3, P 2, O 8

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Znzinc	3	65.38	196.14 w ≈ 50.80%	≈ 50.80%
Pphosphorus	2	30.974	61.948 w ≈ 16.05%	≈ 16.05%
Ooxygen	8	15.999	127.992 w ≈ 33.15%	≈ 33.15%
Σ = 386.08 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

Zn 50.80%

O 33.15%P 16.05%

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Molar masses of substances nearby

Formula	M, g/mol
C₁₂H₂₂O₁₁ (sucrose)	342.297
AgC₁₀H₉N₄SO₂	357.14
Na₂B₄O₇·10H₂O	381.36
Zn₃(PO₄)₂ (zinc phosphate)	386.08
BaI₂ (barium iodide)	391.13
Cr₂(SO₄)₃ (chromium(III) sulfate)	392.16
CHI₃ (iodoform)	393.72

FAQ

What is the molar mass of Zn3(PO4)2?

M(Zn₃(PO₄)₂) = 386.08 g/mol

How to calculate the molar mass of Zn₃(PO₄)₂?

Add up the atomic weights of all the atoms in the formula: 3 × 65.38 + 2 × 30.974 + 8 × 15.999 = 386.08 g/mol.

How many grams are in 2 moles of Zn₃(PO₄)₂?

m = n × M = 2 mol × 386.08 g/mol = 772.16 g.

See Also