Molar Mass of Zn(NO3)2 (Zinc Nitrate)

Molar Mass Calculator

What is the molar mass of Zn(NO₃)₂?

Answer

M(Zn(NO₃)₂) ≈

189.39 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — Zn: 65.38.

Zn(NO₃)₂ = Zn + 2 × (N + 3 O) → Zn 1, N 2, O 6

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Znzinc	1	65.38	65.38 w ≈ 34.52%	≈ 34.52%
Nnitrogen	2	14.007	28.014 w ≈ 14.79%	≈ 14.79%
Ooxygen	6	15.999	95.994 w ≈ 50.69%	≈ 50.69%
Σ = 189.388 ≈ 189.39 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

O 50.69%

Zn 34.52%N 14.79%

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Molar masses of substances nearby

Formula	M, g/mol
Cu(NO₃)₂ (copper(II) nitrate)	187.554
AgBr (silver bromide)	187.77
KC₄H₅O₆ (potassium hydrogen tartrate)	188.176
Zn(NO₃)₂ (zinc nitrate)	189.39
SnCl₂ (stannous chloride)	189.61
TiCl₄ (titanium tetrachloride)	189.67
Os (osmium)	190.23

FAQ

What is the molar mass of Zn(NO3)2?

M(Zn(NO₃)₂) ≈ 189.39 g/mol

How to calculate the molar mass of Zn(NO₃)₂?

Add up the atomic weights of all the atoms in the formula: 65.38 + 2 × 14.007 + 6 × 15.999 = 189.388 ≈ 189.39 g/mol.

How many grams are in 2 moles of Zn(NO₃)₂?

m = n × M = 2 mol × 189.39 g/mol = 378.78 g.

See Also