Molar Mass of V2O5 (Vanadium(V) Oxide)

Molar Mass Calculator

What is the molar mass of V₂O₅?

Answer

M(V₂O₅) =

181.879 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024).

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Vvanadium	2	50.942	101.884 w ≈ 56.02%	≈ 56.02%
Ooxygen	5	15.999	79.995 w ≈ 43.98%	≈ 43.98%
Σ = 181.879 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

V 56.02%O 43.98%

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Molar masses of substances nearby

Formula	M, g/mol
C₉H₈O₄ (aspirin)	180.159
Ta (tantalum)	180.95
(CH₃COO)₂Cu (copper(II) acetate)	181.634
V₂O₅ (vanadium(V) oxide)	181.879
C₆H₁₄O₆ (D-sorbitol)	182.172
C₁₃H₁₀O (benzophenone)	182.222
Ni(NO₃)₂ (nickel(II) nitrate)	182.701

FAQ

What is the molar mass of V2O5?

M(V₂O₅) = 181.879 g/mol

How to calculate the molar mass of V₂O₅?

Add up the atomic weights of all the atoms in the formula: 2 × 50.942 + 5 × 15.999 = 181.879 g/mol.

How many grams are in 2 moles of V₂O₅?

m = n × M = 2 mol × 181.879 g/mol = 363.758 g.

See Also