Molar Mass of NaMnO4 (Sodium Permanganate)

Molar Mass Calculator

What is the molar mass of NaMnO₄?

Answer

M(NaMnO₄) =

141.924 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024).

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Nasodium	1	22.990	22.990 w ≈ 16.20%	≈ 16.20%
Mnmanganese	1	54.938	54.938 w ≈ 38.71%	≈ 38.71%
Ooxygen	4	15.999	63.996 w ≈ 45.09%	≈ 45.09%
Σ = 141.924 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

O 45.09%Mn 38.71%

Na 16.20%

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Molar masses of substances nearby

Formula	M, g/mol
Ce (cerium)	140.12
C₆H₁₂N₄ (methenamine)	140.190
Pr (praseodymium)	140.91
NaMnO₄ (sodium permanganate)	141.924
AsH₃O₄ (arsenic acid)	141.942
P₂O₅ (phosphorus pentoxide)	141.943
Na₂HPO₄ (dibasic sodium phosphate)	141.958

FAQ

What is the molar mass of NaMnO4?

M(NaMnO₄) = 141.924 g/mol

How to calculate the molar mass of NaMnO₄?

Add up the atomic weights of all the atoms in the formula: 22.990 + 54.938 + 4 × 15.999 = 141.924 g/mol.

How many grams are in 2 moles of NaMnO₄?

m = n × M = 2 mol × 141.924 g/mol = 283.848 g.

See Also