Molar Mass of MnCO3 (Manganese Carbonate)

Molar Mass Calculator

What is the molar mass of MnCO₃?

Answer

M(MnCO₃) =

114.946 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024).

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Mnmanganese	1	54.938	54.938 w ≈ 47.79%	≈ 47.79%
Ccarbon	1	12.011	12.011 w ≈ 10.45%	≈ 10.45%
Ooxygen	3	15.999	47.997 w ≈ 41.76%	≈ 41.76%
Σ = 114.946 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

Mn 47.79%O 41.76%

C 10.45%

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Molar masses of substances nearby

Formula	M, g/mol
C₂HF₃O₂ (trifluoroacetic acid)	114.022
C₈H₁₈ (octane)	114.232
In (indium)	114.82
MnCO₃ (manganese carbonate)	114.946
NH₄H₂PO₄ (monobasic ammonium phosphate)	115.025
C₅H₉NO₂ (DL-proline)	115.132
C₄H₄O₄ (fumaric acid)	116.072

FAQ

What is the molar mass of MnCO3?

M(MnCO₃) = 114.946 g/mol

How to calculate the molar mass of MnCO₃?

Add up the atomic weights of all the atoms in the formula: 54.938 + 12.011 + 3 × 15.999 = 114.946 g/mol.

How many grams are in 2 moles of MnCO₃?

m = n × M = 2 mol × 114.946 g/mol = 229.892 g.

See Also