Molar Mass of MnCl2 (Manganese(II) Chloride)

Molar Mass Calculator

What is the molar mass of MnCl₂?

Answer

M(MnCl₂) ≈

125.84 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024); the sum is rounded to the decimal places of the least precise one — Cl: 35.45.

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Mnmanganese	1	54.938	54.938 w ≈ 43.66%	≈ 43.66%
Clchlorine	2	35.45	70.90 w ≈ 56.34%	≈ 56.34%
Σ = 125.838 ≈ 125.84 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

Cl 56.34%Mn 43.66%

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Molar masses of substances nearby

Formula	M, g/mol
C₇H₈O₂ (guaiacol)	124.139
ZnCO₃ (zinc carbonate)	125.39
SrF₂ (strontium fluoride)	125.62
MnCl₂ (manganese(II) chloride)	125.84
Na₂SO₃ (sodium sulfite)	126.04
C₂H₆O₆	126.064
C₅H₆N₂O₂ (thymine)	126.115

FAQ

What is the molar mass of MnCl2?

M(MnCl₂) ≈ 125.84 g/mol

How to calculate the molar mass of MnCl₂?

Add up the atomic weights of all the atoms in the formula: 54.938 + 2 × 35.45 = 125.838 ≈ 125.84 g/mol.

How many grams are in 2 moles of MnCl₂?

m = n × M = 2 mol × 125.84 g/mol = 251.68 g.

See Also