Molar Mass of K3PO4 (Tribasic Potassium Phosphate)
Molar Mass Calculator
What is the molar mass of K3PO4?
Answer
M(K3PO4) =
212.264 g/mol
Atomic weights: IUPAC standard values (CIAAW, 2024).
| Element | Atoms, n | Atomic weight, A | n × A, g/mol Mass fraction, w | |
|---|---|---|---|---|
| Kpotassium | 3 | 39.098 | 117.294 w ≈ 55.26% | ≈ 55.26% |
| Pphosphorus | 1 | 30.974 | 30.974 w ≈ 14.59% | ≈ 14.59% |
| Ooxygen | 4 | 15.999 | 63.996 w ≈ 30.15% | ≈ 30.15% |
| Σ = 212.264 g/mol w = 100% | 100% | |||
Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)
K 55.26%
O 30.15%P 14.59%
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Molar masses of substances nearby
| Formula | M, g/mol |
|---|---|
| BaCl₂ (barium chloride) | 208.23 |
| Bi (bismuth) | 208.98 |
| Sr(NO₃)₂ (strontium nitrate) | 211.63 |
| K₃PO₄ (tribasic potassium phosphate) | 212.264 |
| Al(NO₃)₃ (aluminum nitrate) | 212.994 |
| KIO₃ (potassium iodate) | 214.00 |
| HgO (mercury(II) oxide) | 216.59 |
FAQ
What is the molar mass of K3PO4?
M(K₃PO₄) = 212.264 g/mol
How to calculate the molar mass of K₃PO₄?
Add up the atomic weights of all the atoms in the formula: 3 × 39.098 + 30.974 + 4 × 15.999 = 212.264 g/mol.
How many grams are in 2 moles of K₃PO₄?
m = n × M = 2 mol × 212.264 g/mol = 424.528 g.
See Also
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