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    Molar Mass of KBrO3 (Potassium Bromate)

    Molar Mass Calculator
    Chemical formula

    What is the molar mass of KBrO3?

    Answer

    M(KBrO3) =
    166.999 g/mol

    Atomic weights: IUPAC standard values (CIAAW, 2024).

    Contribution of each element
    Element Atoms, n Atomic weight, A n × A, g/mol Mass fraction, w
    Kpotassium139.09839.098 w ≈ 23.41%
    Brbromine179.90479.904 w ≈ 47.85%
    Ooxygen315.99947.997 w ≈ 28.74%
    Σ = 166.999 g/mol w = 100%

    Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

    Mass fractions of the elements

    O 28.74%K 23.41%

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    Molar Mass of KBrO3 (Potassium Bromate): Step by Step. M(KBrO3) = 166.999 g/mol: 39.098 (K) + 79.904 (Br) + 3 × 15.999 (O). Mass fractions: Br 47.85%, O 28.74%, K 23.41%.
    https://calculat.io/en/other/molar-mass/kbro3/generated.jpgCopy

    FAQ

    What is the molar mass of KBrO3?

    M(KBrO₃) = 166.999 g/mol

    How to calculate the molar mass of KBrO₃?

    Add up the atomic weights of all the atoms in the formula: 39.098 + 79.904 + 3 × 15.999 = 166.999 g/mol.

    How many grams are in 2 moles of KBrO₃?

    m = n × M = 2 mol × 166.999 g/mol = 333.998 g.