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    Molar Mass of KH2PO4 (Monobasic Potassium Phosphate)

    Molar Mass Calculator
    Chemical formula

    What is the molar mass of KH2PO4?

    Answer

    M(KH2PO4) =
    136.084 g/mol

    Atomic weights: IUPAC standard values (CIAAW, 2024).

    Contribution of each element
    Element Atoms, n Atomic weight, A n × A, g/mol Mass fraction, w
    Kpotassium139.09839.098 w ≈ 28.73%
    Hhydrogen21.00802.0160 w ≈ 1.48%
    Pphosphorus130.97430.974 w ≈ 22.76%
    Ooxygen415.99963.996 w ≈ 47.03%
    Σ = 136.084 g/mol w = 100%

    Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

    Mass fractions of the elements

    K 28.73%P 22.76%H 1.48%

    See Also

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    Molar Mass of KH2PO4 (Monobasic Potassium Phosphate). M(KH2PO4) = 136.084 g/mol: 39.098 (K) + 2 × 1.0080 (H) + 30.974 (P) + 4 × 15.999 (O). Mass fractions: O 47.03%, K 28.73%, P 22.76%.
    https://calculat.io/en/other/molar-mass/kh2po4/generated.jpgCopy

    FAQ

    What is the molar mass of KH2PO4?

    M(KH₂PO₄) = 136.084 g/mol

    How to calculate the molar mass of KH₂PO₄?

    Add up the atomic weights of all the atoms in the formula: 39.098 + 2 × 1.0080 + 30.974 + 4 × 15.999 = 136.084 g/mol.

    How many grams are in 2 moles of KH₂PO₄?

    m = n × M = 2 mol × 136.084 g/mol = 272.168 g.