Molar Mass of Ca3(PO4)2 (Tricalcium Phosphate)

Molar Mass Calculator

What is the molar mass of Ca₃(PO₄)₂?

Answer

M(Ca₃(PO₄)₂) =

310.174 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024).

Ca₃(PO₄)₂ = 3 Ca + 2 × (P + 4 O) → Ca 3, P 2, O 8

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Cacalcium	3	40.078	120.234 w ≈ 38.76%	≈ 38.76%
Pphosphorus	2	30.974	61.948 w ≈ 19.97%	≈ 19.97%
Ooxygen	8	15.999	127.992 w ≈ 41.26%	≈ 41.26%
Σ = 310.174 g/mol w = 100%				100%

Each fraction is rounded on its own, so the printed ones add up to 99.99%; unrounded, they make exactly 100%.

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

O 41.26%Ca 38.76%

P 19.97%

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Molar masses of substances nearby

Formula	M, g/mol
C₁₅H₁₀O₇ (quercetin)	302.238
PbSO₄ (lead sulfate)	303.3
Ba(ClO₃)₂ (barium chlorate)	304.22
Ca₃(PO₄)₂ (tricalcium phosphate)	310.174
Ag₂SO₄ (silver sulfate)	311.80
C₂₀H₁₄O₄ (phenolphthalein)	318.328
ZnI₂ (zinc iodide)	319.18

FAQ

What is the molar mass of Ca3(PO4)2?

M(Ca₃(PO₄)₂) = 310.174 g/mol

How to calculate the molar mass of Ca₃(PO₄)₂?

Add up the atomic weights of all the atoms in the formula: 3 × 40.078 + 2 × 30.974 + 8 × 15.999 = 310.174 g/mol.

How many grams are in 2 moles of Ca₃(PO₄)₂?

m = n × M = 2 mol × 310.174 g/mol = 620.348 g.

See Also