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    Molar Mass of CaCrO4 (Calcium Chromate)

    Molar Mass Calculator
    Chemical formula

    What is the molar mass of CaCrO4?

    Answer

    M(CaCrO4) =
    156.070 g/mol

    Atomic weights: IUPAC standard values (CIAAW, 2024).

    Contribution of each element
    Element Atoms, n Atomic weight, A n × A, g/mol Mass fraction, w
    Cacalcium140.07840.078 w ≈ 25.68%
    Crchromium151.99651.996 w ≈ 33.32%
    Ooxygen415.99963.996 w ≈ 41.00%
    Σ = 156.070 g/mol w = 100%

    Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

    Mass fractions of the elements

    Cr 33.32%Ca 25.68%

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    Molar Mass of CaCrO4 (Calcium Chromate): Step by Step. M(CaCrO4) = 156.070 g/mol: 40.078 (Ca) + 51.996 (Cr) + 4 × 15.999 (O). Mass fractions: O 41.00%, Cr 33.32%, Ca 25.68%.
    https://calculat.io/en/other/molar-mass/cacro4/generated.jpgCopy

    FAQ

    What is the molar mass of CaCrO4?

    M(CaCrO₄) = 156.070 g/mol

    How to calculate the molar mass of CaCrO₄?

    Add up the atomic weights of all the atoms in the formula: 40.078 + 51.996 + 4 × 15.999 = 156.070 g/mol.

    How many grams are in 2 moles of CaCrO₄?

    m = n × M = 2 mol × 156.070 g/mol = 312.140 g.