Molar Mass of Ca(H2PO4)2 (Monocalcium Phosphate)

Molar Mass Calculator

What is the molar mass of Ca(H₂PO₄)₂?

Answer

M(Ca(H₂PO₄)₂) =

234.050 g/mol

Atomic weights: IUPAC standard values (CIAAW, 2024).

Ca(H₂PO₄)₂ = Ca + 2 × (2 H + P + 4 O) → Ca 1, H 4, P 2, O 8

Contribution of each element
Element	Atoms, n	Atomic weight, A	n × A, g/mol Mass fraction, w	Mass fraction, w
Cacalcium	1	40.078	40.078 w ≈ 17.12%	≈ 17.12%
Hhydrogen	4	1.0080	4.0320 w ≈ 1.72%	≈ 1.72%
Pphosphorus	2	30.974	61.948 w ≈ 26.47%	≈ 26.47%
Ooxygen	8	15.999	127.992 w ≈ 54.69%	≈ 54.69%
Σ = 234.050 g/mol w = 100%				100%

Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)

Mass fractions of the elements

O 54.69%

P 26.47%Ca 17.12%H 1.72%

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Molar masses of substances nearby

Formula	M, g/mol
Th (thorium)	232.04
HgS (mercury(II) sulfide)	232.65
BaSO₄ (barium sulfate)	233.39
Ca(H₂PO₄)₂ (monocalcium phosphate)	234.050
AgI (silver iodide)	234.77
CdN₂O₆ (cadmium nitrate)	236.42
U (uranium)	238.03

FAQ

What is the molar mass of Ca(H2PO4)2?

M(Ca(H₂PO₄)₂) = 234.050 g/mol

How to calculate the molar mass of Ca(H₂PO₄)₂?

Add up the atomic weights of all the atoms in the formula: 40.078 + 4 × 1.0080 + 2 × 30.974 + 8 × 15.999 = 234.050 g/mol.

How many grams are in 2 moles of Ca(H₂PO₄)₂?

m = n × M = 2 mol × 234.050 g/mol = 468.100 g.

See Also