Molar Mass of C6H7N3O (Isoniazid)
Molar Mass Calculator
What is the molar mass of C6H7N3O?
Answer
M(C6H7N3O) =
137.142 g/mol
Atomic weights: IUPAC standard values (CIAAW, 2024).
| Element | Atoms, n | Atomic weight, A | n × A, g/mol Mass fraction, w | |
|---|---|---|---|---|
| Ccarbon | 6 | 12.011 | 72.066 w ≈ 52.55% | ≈ 52.55% |
| Hhydrogen | 7 | 1.0080 | 7.0560 w ≈ 5.15% | ≈ 5.15% |
| Nnitrogen | 3 | 14.007 | 42.021 w ≈ 30.64% | ≈ 30.64% |
| Ooxygen | 1 | 15.999 | 15.999 w ≈ 11.67% | ≈ 11.67% |
| Σ = 137.142 g/mol w = 100% | 100% | |||
Each fraction is rounded on its own, so the printed ones add up to 100.01%; unrounded, they make exactly 100%.
Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)
C 52.55%
N 30.64%O 11.67%H 5.15%
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FAQ
What is the molar mass of C6H7N3O?
M(C₆H₇N₃O) = 137.142 g/mol
How to calculate the molar mass of C₆H₇N₃O?
Add up the atomic weights of all the atoms in the formula: 6 × 12.011 + 7 × 1.0080 + 3 × 14.007 + 15.999 = 137.142 g/mol.
How many grams are in 2 moles of C₆H₇N₃O?
m = n × M = 2 mol × 137.142 g/mol = 274.284 g.
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