Molar Mass of C3H5N3O9 (Nitroglycerin)
Molar Mass Calculator
What is the molar mass of C3H5N3O9?
Answer
M(C3H5N3O9) =
227.085 g/mol
Atomic weights: IUPAC standard values (CIAAW, 2024).
| Element | Atoms, n | Atomic weight, A | n × A, g/mol Mass fraction, w | |
|---|---|---|---|---|
| Ccarbon | 3 | 12.011 | 36.033 w ≈ 15.87% | ≈ 15.87% |
| Hhydrogen | 5 | 1.0080 | 5.0400 w ≈ 2.22% | ≈ 2.22% |
| Nnitrogen | 3 | 14.007 | 42.021 w ≈ 18.50% | ≈ 18.50% |
| Ooxygen | 9 | 15.999 | 143.991 w ≈ 63.41% | ≈ 63.41% |
| Σ = 227.085 g/mol w = 100% | 100% | |||
Atomic weights: CIAAW, Abridged Standard Atomic Weights (2024)
O 63.41%
N 18.50%C 15.87%H 2.22%
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Molar masses of substances nearby
| Formula | M, g/mol |
|---|---|
| C₃H₆N₆O₆ (cyclonite) | 222.117 |
| PbO (lead(II) oxide) | 223.2 |
| ZnBr₂ (zinc bromide) | 225.19 |
| C₃H₅N₃O₉ (nitroglycerin) | 227.085 |
| C₇H₅N₃O₆ (TNT) | 227.132 |
| SbCl₃ (antimony trichloride) | 228.11 |
| C₁₄H₁₂O₃ (resveratrol) | 228.247 |
FAQ
What is the molar mass of C3H5N3O9?
M(C₃H₅N₃O₉) = 227.085 g/mol
How to calculate the molar mass of C₃H₅N₃O₉?
Add up the atomic weights of all the atoms in the formula: 3 × 12.011 + 5 × 1.0080 + 3 × 14.007 + 9 × 15.999 = 227.085 g/mol.
How many grams are in 2 moles of C₃H₅N₃O₉?
m = n × M = 2 mol × 227.085 g/mol = 454.170 g.
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